Flow of a Vector Field
Section 3: Flow of a Vector Field
3 Flow of a Vector Field
A geometric way of looking upon dierentiation in R
n
is the following. Suppose given
a vector a = (a
1
, . . . , a
n
). For any t ∈ R, consider the transformation φ
t
: (x
1
, . . . , x
n
) 7→
(x
1
+ ta
1
, . . . , x
n
+ ta
n
) of R
n
into itself. This is a homomorphism of the additive group
R into the group of dieomorphisms of R
n
. For any dierentiable function f on R
n
,
dene
(D
a
(f))(x) = lim
t→0
f(φ
t
(x)) −f(x)
t
This exists and in fact denes the dierential operator
a
i
∂
∂x
i
. We may generalise this
idea to an arbitrary dierential manifold. Let (φ
t
), t ∈ R, be a one-parameter group of
dieomorphisms of M in the sense that
i) the map R ×M → M given by (t, x) 7→ φ
t
(x) is dierentiable.
ii) the map φ
0
: M → M is the identity.
iii) φ
t
◦ φ
t
′
= φ
t+t
′
for all t, t
′
∈ R.
Then we may dene dierentiation of functions f with respect to the above data by
setting
(X
φ
f)(x) = lim
t→0
f(φ
t
(x)) −f(x)
t
It is easy to see that X
φ
is indeed a homogeneous rst order operator (i.e. a vector
eld). In fact, the linearity of X
φ
is obvious, while we have for every f, g ∈ A(M ),
(X
φ
(fg))(x) = lim
t
→
0
f(φ
t
(x))
g(φ
t
(x)) −g(x)
t
+ lim
t
→
0
g(x)
f(φ
t
(x)) −f(x)
t
= f(x)(X
φ
g)(x) + g(x)(X
φ
f)(x).
3.1. Examples.
1) Take M = R and φ
t
(x) = x + t for all t, x ∈ R.
2) Take M = R and φ
t
(x) = e
t
x, for all t, x ∈ R.
In these two cases, we see that the associated operators are respectively
d
dx
and
x
d
dx
.
3) Again take M = R and consider the function φ
t
(x) =
x
1−tx
. It is easy to see
formally that φ
t
◦φ
t
′
= φ
t+t
′
. But, for any given x 6= 0, φ
t
(x) is only dened for t <
1/x. We are dealing here with a local 1-parameter group of local automorphisms.
In other words, for any x there exist a neighbourhood U and ϵ > 0, such that
φ
t
(y) is dened for all |t| < ϵ and y ∈ U . The group condition iii) above is
45
Chapter II: Differential Operators
satised to the extent it makes sense. But notice that the associated vector eld
is still meaningful.
3.2. Exercises.
1) Compute the vector eld given in Example 3) above.
2) Determine the vector eld given by the one-parameter group (φ
t
) whose action on
R
2
is given by
φ
t
(v, w) = (cos(t)v + sin(t)w, −sin(t)v + cos(t)w).
With this extended notion we have a converse.
3.3. Theorem. Let X be a vector eld on a dierential manifold M. Then for every
x ∈ M , there exist an open neighbourhood U of x, ϵ > 0, and maps φ
t
: U → M for all
|t| < ϵ, satisfying:
i) the map (−ϵ, ϵ) ×U → M given by (t, y) 7→ φ
t
(y) is dierentiable.
ii) the map φ
0
: U → M is the inclusion.
iii) (φ
t
◦ φ
t
′
)(y) = φ
t+t
′
(y) for all |t|, |t
′
| < ϵ and y ∈ M such that |t + t
′
| < ϵ and
y, φ
t
′
(y) are in U .
iv) X
φ
= X.
Proof. Since X
φ
and X are both vector elds, the assertion is purely local and so we may
replace M by an open set in R
n
and prove the existence of maps φ
t
such that X
φ
x
i
= Xx
i
for all i. This reduces our task to showing the following. Given dierentiable functions
a
i
, we need to nd functions
φ(t, x) : (−ϵ, ϵ) × U → R
n
for some neighbourhood U of a given point such that
lim
t→0
φ
i
(t, x) −x
i
t
= a
i
(x), for all i.
This implies that
∂
∂t
φ
i
(t, x) = lim
t
′
→0
φ
i
(t
′
+ t, x) − φ
i
(t, x)
t
′
= lim
t
′
→0
φ
i
(t
′
, φ(t, x)) −φ
i
(t, x)
t
′
= a
i
(φ(t, x)).
46
Section 3: Flow of a Vector Field
We also have the initial condition φ
i
(0, x) = x
i
. So we start with this equation and
note that it has a unique solution in a neighbourhood of (0, x) in R × R
n
. To prove
that iii) is satised, we use the uniqueness of the solution. In fact, both φ(t + t
′
, x)
and φ(t, φ(t
′
, x)) are solutions of the equation
d
dt
ψ
i
(t, x) = a
i
(ψ(t, x)) with the initial
condition ψ
i
(0, x) = φ
i
(t
′
, x). Finally equation iv) is obvious from the construction.
From this point of view, the term ‘innitesimal transformation’ is an appropriate
alternative to that of a ‘vector eld’.
3.4. Denition. The one-parameter group associated to a vector eld is called the
ow of the vector eld.
3.5. Remarks.
1) Although a vector eld gives rise in general only to a local 1-parameter group,
a limited globalization is possible. Indeed, given a compact set K ⊂ M , we can
dene φ
t
in a neighbourhood of K for all |t| < ϵ. For, by Theorem 3.3 this can be
done in a neighbourhood of every point of K. Since K can be covered by nitely
many of these neighbourhoods, φ
t
(y) are dened in the same open set |t| < ϵ for
small enough ϵ, and for y in a neighbourhood of K. In particular, if M is itself
compact, then φ
t
is dened as an automorphism of M for all |t| < ϵ, and hence
by iteration, we get in this case, a global ow.
2) It is obvious that if X depends dierentiably on some parameters s, then the
one-parameter group is dened for small values of the parameters and depends
dierentiably on them.
3.6. Denition. A vector eld which gives rise to a global ow is said to be complete.
We have seen above that any vector eld on a compact manifold is complete. It is
easily seen that the vector eld x
2
d
dx
on R is not complete.
47
Chapter II: Differential Operators
3.7. Exercise. Let M be a compact manifold and X a vector eld. If m ∈ M,
determine when the restriction of X to the open submanifold M \ {m} is complete.
3.8. Denition. If X is a vector eld and (φ
t
) the ow corresponding to it, the orbit
of a point m ∈ M under φ
t
, namely the map t 7→ φ
t
(m), is called an integral curve for
X.
3.9. Remark. The integral curve of a vector eld X has the property that the dier-
ential of this map at t maps
d
dt
to X
φ
t
(m)
. This characterises the curve. In particular,
the curve degenerates to a constant map if and only if X
m
= 0. If X is 0 at a point m, we
say that m is a singularity of X. Our remark amounts to saying that the one-parameter
group φ
t
xes a point m if and only if m is a singularity of X.
Suppose that m is not a singularity. Then by continuity, we see that X
x
6= 0 for all x
in a neighbourhood of m. Now the integral curve has injective dierential at all points
near 0 and hence it is an immersed manifold of dimension 1. Actually there is a local
coordinate system (U, x) in which X is given by
∂
∂x
1
. Indeed, suppose X =
a
i
∂
∂x
i
,
where by our assumption one of the a
i
’s, say a
1
, is nonzero. Consider the coordinate
system given by (y
1
, . . . , y
n
) where y
i
= φ
x
1
(x
1
, 0, x
2
, . . . , x
n
). We now compute the
partial derivatives
∂y
i
∂x
j
at m given by x
i
= 0 for all i:
∂y
i
∂x
1
= a
i
(0);
∂y
i
∂x
j
= δ
i,j
for j ≥ 2
This shows that (y
1
, . . . , y
n
) is a coordinate system in a neighbourhood of m. It is easy
to see that this coordinate system serves the purpose.
Invariant vector elds. We wish to study now vector elds on a Lie group.
3.10. Denition. Suppose M is dierential manifold and a Lie group G acts on it.
Then a vector eld X on M is said to be invariant under the action if the transform of
X by any element of G is the same as X, that is to say, for every m ∈ M and g ∈ G,
X
gm
is the image of the vector X
m
under the dierential at m of the map x 7→ gx of M
into itself.
From the uniqueness of the ow corresponding to a vector eld, we deduce that if
the ow of X is φ
t
, then the ow corresponding to gX is given by ψ
t
(m) = gφ
t
(g
−1
m).
Therefore, if X is invariant under G, then the ows ψ
t
and φ
t
are the same, so that φ
t
commutes with the action of G for all t.
Notice also that from the denition of Lie brackets of vector elds it follows that if
X and Y are G-invariant, then [X, Y ] is also invariant. In particular, the vector space
of invariant vector elds is actually a Lie algebra. We have already remarked that G
acts on itself by left translations and so left invariant vector elds of a Lie group form
a Lie algebra over R.
48
Section 3: Flow of a Vector Field
3.11. Denition. Let G be a connected Lie group. The Lie algebra of vector elds
which are left invariant (i.e. invariant under left translation by elements of G) is called
the Lie algebra of G, and is often denoted by Lie(G) or g.
3.12. Remark. There is a natural linear map of g into the tangent space T
1
(G) at
1, given by X 7→ X
1
. It is an isomorphism and the inverse associates to any vector
v ∈ T
1
(G), the vector eld X given by X
g
= L
g
(v), where L
g
denotes the dierential at
1 of the left translation by g. So g is a Lie algebra of dimension n = dim(G).
3.13. Examples.
1) The left invariant vector elds on the additive Lie group R are of the form a
d
dt
,
a ∈ R. Hence the Lie algebra of R is canonically isomorphic to the abelian Lie
algebra R. In the same way, if we take the additive Lie group underlying a vector
space V , then its Lie algebra is identied with the abelian Lie algebra V .
2) On the other hand, if we take the multiplicative group R
×
or its connected compo-
nent R
+
containing 1, then the invariant vector elds are scalar multiples of t
d
dt
.
Thus its Lie algebra is also the abelian Lie algebra R.
3) The Lie algebra of the group GL(n, R) or the connected component GL(n, R)
+
containing 1, can be identied with M(n, R). It is clear that the tangent space at
1 of this open submanifold is canonically
M
(
n
)
as a vector space. It only remains
to compute the Lie algebra structure. Denote by x
ij
the function which associates
to any matrix A its (i, j)-th coecient. Let A ∈ M (n) and X be the left invariant
vector eld on GL(n) such that X
1
(x
ij
) = A
ij
. For any s ∈ GL(n, R)
+
, we have
X
s
(x
ij
) = X
1
(x
ij
◦L
s
), where L
s
is left translation by s. Hence the function Xx
ij
is given by s 7→
k
x
ik
(s)X
1
x
kj
=
x
ik
A
kj
. If Y is any left invariant vector eld
with Y
1
(x
ij
) = B
ij
, then we have
(XY − Y X)
1
(x
ij
) = X
1
(Y x
ij
) − Y
1
(Xx
ij
)
= X
1
(
x
ik
B
kj
) − Y
1
(
x
ik
A
kj
)
=
A
ik
B
kj
−
B
ik
A
kj
= (AB − BA)
ij
.
In other words, if we identify left invariant vector elds on GL(n) with M(n),
then the Lie bracket is given by the bracket associated with the multiplication in
the matrix algebra.
3.14. Exercises.
1) Show that the left invariant vector elds on GL(n) are generated by E
p,q
=
x
i,p
∂
∂x
i,q
and that the right invariant vector elds by F
p,q
=
x
q,j
∂
∂x
p,j
.
49
Chapter II: Differential Operators
2) Deduce that E
p,q
and F
r,s
commute. Explain this in terms of their ows.
The integral curve through 1 of a left invariant vector eld, namely t 7→ φ
t
(1), is
actually a homomorphism of the group R into G. In fact, left invariance of X implies
that for every g ∈ G, the automorphism x 7→ gφ
t
(x) is the same as x 7→ φ
t
(gx). Taking
g = φ
t
(1), we get φ
t
′
(1)φ
t
(1) = φ
t
(φ
t
′
(1)) = φ
t+t
′
(1).
3.15. Denition. A dierentiable group homomorphism of the Lie group R into a
Lie group G is called a one-parameter group.
If ρ : R → G is a 1-parameter group, then ρ
d
dt
gives a vector at 1 which in turn
denes a left invariant vector eld X. It is clear that ρ gives an integral curve for X.
3.16. Remarks.
1) If the vector eld X is 0, the corresponding one-parameter group is the constant
homomorphism t 7→ 1. Even if X is not 0, the map t 7→ φ
t
(1) mentioned above,
may not be injective. If we take G = S
1
= {(x, y) ∈ R
2
: x
2
+ y
2
= 1}, then
the left invariant vector elds form a 1-dimensional vector space generated by
X = x
∂
∂y
− y
∂
∂x
. The image of
d
dt
under the map t 7→ (cos at, sin at) is easily
computed to be aX. Hence it is the one-parameter group of the vector eld aX.
Its kernel is the subgroup
2π
a
Z of R.
2) Also the image of a one-parameter group is not in general closed. For example,
consider the case when G = S
1
× S
1
and X =
d
dt
, a
d
dt
. Then the induced
one-parameter group is given by
t 7→ ((cos t, sin t), ( cos at, sin at)).
This is a closed submanifold if and only if a is rational. See the gure in [Ch. 1,
3.17].
3) If g ∈ G, then (the dierential of) the inner automorphism x 7→ gxg
−1
of G
takes the vector eld X to another left invariant vector eld which we may denote
gXg
−1
. If t 7→ c(t) is the ow of X, then the ow of gXg
−1
is given by t 7→
gc(t)g
−1
.
3.17. Denition. The representation of a Lie group G into GL(g) which associates
to g ∈ G the automorphism Ad(g) = X 7→ gXg
−1
is called the adjoint representation
of G.
3.18. Remark. The linear automorphism Ad(g) is actually an automorphism of the
Lie algebra g.
3.19. Exercise. Show that if the image of the one-parameter group is closed, then it
is actually a closed submanifold.
50
Section 3: Flow of a Vector Field
If G and H are Lie groups and T : G → H is a homomorphism of Lie groups, then
the dierential at 1 is a linear map T
1
(G) → T
1
(H). As such it gives a linear map
t : g → h as well, using the isomorphisms T
1
(G) → g and T
1
(H) → h.
3.20. Proposition. Let X, Y be left invariant vector elds of a Lie group G. If
T : G → H is a homomorphism of Lie groups, then we have
t[X, Y ] = [t(X), t( Y )].
Proof. Let f be a dierentiable function in a neighbourhood of 1 in H. Then for any
Z ∈ h and any x ∈ G, we have (Zf)(T x) = Z
1
(L
T x
f), since Z is an invariant vector
eld. Let us take Z = tX, that is to say, Z is the left invariant vector eld whose value
in T
1
(H) is the image of X
1
∈ T
1
(G) by the dierential at 1 of T . Then Z
1
(L
T x
f) =
X
1
(L
T x
f ◦ T ) = X
1
(L
x
(f ◦ T )) = X
x
(f ◦ T ) since X is left invariant. In other words,
(tX)(f) ◦ T = X(f ◦ T ). Hence if Y ∈ g, we may replace f by (tY )f in this equation
and obtain (tX)(tY )(f) ◦ T = X(( tY )f ◦T ) = XY (f ◦T ). Interchanging X and Y and
subtracting, we get [tX, tY ]( f ) ◦ T = [X, Y ](f ◦ T ). Evaluating at 1, we see that the
image of [X, Y ] under the dierential of T at 1 is actually [t(X), t(Y )]. This proves our
assertion.
We have remarked that if a vector eld depends dierentiably on some parameters,
then its ow also depends dierentiably on the parameters. From this it also follows that
the one-parameter group associated to a left invariant vector eld depends dierentiably
on it, meaning that there exists a dierentiable map ρ : T
1
(G) × R → G such that
for any X ∈ T
1
(G) the map t 7→ ρ(X, t) is the corresponding one-parameter group.
The restriction of ρ to T
1
(G) × {1} is a dierentiable map g → G. This is called the
exponential mapping. Let v ∈ T
1
(G). Then we will evaluate at v, the dierential at 0
of the exponential. We might as well restrict ρ to Rv × R rst in order to compute this
dierential. In other words, we consider the map (sv, t) 7→ c(sv, t) but this is the same
as c(v, st). Setting t = 1, we need to compute the dierential of s 7→ c(v, s) at s = 0.
By denition it is v. In other words, we have shown
3.21. Proposition. The dierential at 0 of the exponential map from g to G is the
identity map. In particular, the exponential map gives a dieomorphism of a neigh-
bourhood of 0 in g onto a neighbourhood of 1 in G.
It follows from the uniqueness assertion regarding one-parameter groups, that if
T : G → H is a dierentiable homomorphism of connected Lie groups, the induced map
t commutes with the exponential map in the sense that exp
H
◦t = T ◦ exp
G
.
If T, T
′
: G → H are two homomorphisms of connected Lie groups such that the
induced homomorphisms t, t
′
are the same, then T = T
′
. For from Proposition 3.22, our
51
Chapter II: Differential Operators
assumption implies that T and T
′
coincide in a neighbourhood of 1 in G. But if G is
connected, any neighbourhood U of 1 generates G as a group. Hence T, T
′
coincide on
the whole of G.
Moreover, if a homomorphism T : G → H of connected Lie groups is injective, then
the induced homomorphism t is also injective. For if X is in the kernel of t, then the
image of the one-parameter group t 7→ T (exp(tX)) has tangent 0 at 1 and should be the
constant homomorphism. By our assumption, the map t 7→ exp(tX) is also constant,
and hence X = 0.
Conversely, if t is injective, the kernel of T cannot intersect the exponential neigh-
bourhood, and is therefore a discrete normal subgroup of G.
Finally, if t is an isomorphism of Lie algebras, then T has discrete kernel N and goes
down to a homomorphism of the Lie group G/N into H. This induces an isomorphism
at the Lie algebra level. Since the dierential of T at 1 and hence at any other point
is an isomorphism, it is a dieomorphism onto an open subgroup of H. Since H is
connected, the image coincides with H. In other words, T : G → H is an isomorphism.
3.22. Remark. We have associated to every Lie group, a Lie algebra and to every Lie
group homomorphism, a Lie algebra homomorphism of the corresponding Lie algebras.
This correspondence helps one to understand an analytical object such as a Lie group,
by a purely algebraic object, namely its Lie algebra.
52