Tensor Fields and Lie Derivative
Section 5: Tensor Fields; Lie Derivative
5 Tensor Fields; Lie Derivative
The usual algebraic operations that one performs on vector spaces may also be done
on vector bundles. Thus if E and F are dierentiable vector bundles, then their tensor
product E ⊗ F may be dened as follows. Consider the set E ⊗ F =
x∈M
E
x
⊗ F
x
.
It can be made into a dierential manifold by noting that when E varies over a small
enough open set U around any point, this union can be identied with U ×(R
k
⊗R
l
) by
using local trivialisations of E and F . Identifying R
k
⊗ R
l
with R
kl
, we may introduce
a dierentiable structure on
x∈U
E
x
⊗ F
x
. It is easy to see that these structures do
not depend on the particular local trivialisations one uses, and consequently glue up
to provide a dierential structure on E ⊗ F . It is clear how to dene a vector bundle
structure on this space. The dual E
∗
as well as the tensor, exterior and symmetric
powers of a vector bundle E may also be dened in a similar way. If E and F are the
locally free sheaves of A-modules corresponding to E and F , then the tensor product
E ⊗ F is the vector bundle associated to the presheaf which assigns to any open set U
the A(U )-module E(U) ⊗
A(U)
F(U ). Its stalk at any point x ∈ M is easily seen to be
E
x
⊗
A
x
F
x
.
On a dierential manifold M , many interesting geometric objects are described by
sections of vector bundles, usually the tensor powers of the tangent bundle and its dual,
the cotangent bundle. We will only deal with dierentiable sections even if we do not
say so explicitly each time.
Sections of the cotangent bundle are called dierential forms of degree 1 and sections
of its p-th exterior power Λ
p
(T
∗
) are called dierential forms of degree p. Note that
there are no nonzero dierential forms of degree greater than the dimension of M. A
dierential form of degree p may also be regarded as an alternating A(M )-multilinear
form of degree p on the space of vector elds (i.e. takes the value 0, whenever two of
the argument vector elds are equal). With this interpretation, one can see that the
exterior product of two dierential forms α, β of degree p and q is given by
(α ∧ β)(X
1
, . . . , X
p+q
)
=
ϵ
σ
α(X
σ (1)
, . . . , X
σ (p )
)β(X
σ (p +1)
, . . . , X
σ (p +q)
)
where σ runs through the so-called ‘shue’ permutations and ϵ
σ
is the signature of
σ. (A shue is a permutation which preserves the relative orders in the two subsets,
that is to say, it is a permutation of {1, . . . , k + l} such that σ(1) < ··· < σ(p) and
σ(p + 1) < ··· < σ(p + q).)
In order to develop dierential calculus on a dierential manifold M , we rst need
the notion of dierentiation of a tensor eld. We then seek to dene the derivative of a
tensor eld, namely a section of
r
T ⊗
s
T
∗
, with respect to a vector eld X. The most
natural denition that one might give, following the geometric denition of a vector eld
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Chapter II: Differential Operators
as an innitesimal transformation given above, is the following.
5.2. Denition. If ω is a tensor eld, then the Lie derivative L(X)(ω) of ω with
respect to X is
lim
t→0
(φ
∗
t
ω − ω)
t
where φ
t
is the ow determined by X.
It is not dicult to show that the above limit exists if (as we assume) the vector
eld X and the tensor eld in question are dierentiable. Note that the automorphisms
φ
t
give also isomorphisms φ
∗
t
between tensors at any point m ∈ M and those at φ
t
(m).
With this understanding, the above denition amounts to saying that the value of the
tensor eld L(X)(ω) at any point m ∈ M is the tensor lim
t→0
(φ
∗
t
ω
φ
t
(m)
−ω
m
)
t
. This
is the obvious generalisation of the action of X on functions, that is to say, we have
L(X)f = Xf for functions f .
Imitating the proof for the product rule for dierentiation, one can show the follow-
ing.
5.3. Proposition. Assume given an A-bilinear sheaf homomorphism (ω, ω
′
) 7→
B(ω, ω
′
) which associates to any two tensor elds ω, ω
′
of xed types, a third one.
Assume that for any dieomorphism φ of an open submanifold U with U
′
, we have
B(φ
∗
ω, φ
∗
ω
′
) = φ
∗
B(ω, ω
′
). Then for any vector eld X on M , the following identity
holds:
L(X)B(ω, ω
′
) = B(L(X)ω, ω
′
) + B(ω, L(X)ω
′
).
Proof. In fact, by denition, (L(X)B(ω, ω
′
))
p
is
= lim
t→0
φ
∗
t
B(ω, ω
′
)
φ
t
(p)
− B(ω, ω
′
)
p
t
= lim
t→0
B(φ
∗
t
ω
φ
t
(p)
, φ
∗
t
ω
′
φ
t
(p)
) −B(ω
p
, ω
′
p
)
t
= lim
t
→
0
B(φ
∗
t
ω
φ
t
(p)
− ω
p
, φ
∗
t
ω
′
φ
t
(p)
) + B(ω
p
, φ
∗
t
ω
′
φ
t
(p)
− ω
′
p
)
t
= B
lim
t→0
φ
∗
t
ω
φ
t
(p)
− ω
p
t
, φ
∗
t
ω
′
φ
t
(p)
+ B
ω
p
, lim
t→0
φ
∗
t
ω
′
φ
t
(p)
− ω
′
p
t
= B(L(X)ω, ω
′
)
p
+ B(ω, L(X)ω
′
)
p
.
5.4. Corollary.
58
Section 5: Tensor Fields; Lie Derivative
i) If ω, ω
′
are tensor elds, then
L(X)(ω ⊗ ω
′
) = L(X)ω ⊗ ω
′
+ ω ⊗ L(X)ω
′
.
ii) If α, β are dierential forms, then
L(X)(α ∧ β) = L( X)α ∧β + α ∧ L(X)β.
iii) If ω is a dierential form of degree 1 and X, Y are vector elds, then
X(ω(Y )) = (L(X)ω)(Y ) + ω(L(X)Y ).
Proof. We simply have to take in the above proposition the map B to be
i) ( ω, ω
′
) 7→ ω ⊗ ω
′
;
ii) ( α, β) 7→ α ∧β;
iii) ( ω, Y ) 7→ ω(Y ).
5.5. Remark. From the denition of Lie derivation it is easy to deduce that if
L(X)ω = 0, then ω is left invariant under the ow of X, i.e. φ
t
takes ω to itself. Hence
we give the following denition.
5.6. Denition. Let X be a vector eld and ω a tensor eld. Then we say that ω is
invariant under X if L(X)ω = 0.
5.7. Computation of L(X). In Proposition 5.2, we assumed that B is A-bilinear,
but used mainly that it was R-bilinear. The only point at which we used A-linearity was
when we took the limit inside the argument in B. Notice that if X, ω are dierentiable
(as we always assume), then the limit as t tends to zero, of
(φ
t
)
∗
ω − ω
t
, namely
L
(
X
)(
ω
)
,
exists even uniformly on compact sets. Indeed this exists even uniformly for the partial
derivatives. We do not wish to go into this question extensively because it is irrelevant
to the present discussion. We mention it only to point out that the conclusion of
Proposition 5.2 is valid even when B is not A-bilinear but satises a suitable continuity
axiom. We will apply this to the following examples in which in any case the identity
can be directly checked.
5.8. Examples.
1) ( Y, f ) 7→ Y f where Y is a vector eld and f is a function. The corresponding
identity gives X(Y f ) = L(X)(Y ) + Y Xf , which computes the Lie derivatives on
59
Chapter II: Differential Operators
vector elds to be
L(X)(Y ) = XY −Y X.
2) ( Y, Z) 7→ [Y, Z], where Y, Z are vector elds. Then we get, using the above com-
putation, that
[X, [Y, Z]] = [[X, Y ], Z] + [Y, [X, Z]]
which is just the Jacobi identity.
3) The above identity can also be rewritten as
L([X, Y ]) = L(X)L(Y ) −L(Y )L(X)
on vector elds. It is easy to see that this is valid even for derivatives of other
tensor elds.
5.9. Remark. From Remark 5.4, we conclude that if X and Y are commuting vector
elds, that is to say, [X, Y ] = 0, then the ow φ
t
of X leaves Y xed. If ψ
t
is the ow of
Y , then it follows that the group φ
t
′
◦ψ
t
◦(φ
t
′
)
−1
gives rise to the vector eld φ(Y ) = Y .
The uniqueness of the ow therefore implies that φ
t
and ψ
t
commute for all t, t
′
.
Corollary 5.3 also computes L( X) on dierential forms. Firstly, on forms of degree
1, we have, by 5.4, iii),
(L(X)ω)(Y ) = Xω(Y ) −ω([X, Y ]),
while 5.4, ii) gives the computation on dierential forms of higher degree. Indeed, we
get
(L(X)α)(X
1
, . . . , X
p
) = Xα(X
1
, . . . , X
p
) −
p
i=1
α(X
1
, . . . , [X, X
i
], . . . , X
p
).
While the Lie derivative is a good notion of dierentiation of a tensor eld with
respect to a vector eld, it does not lead to a notion of dierentiation of a tensor eld
with respect to a tangent vector at a point. The reason for this is that the value of the
Lie derivative of a tensor eld at a point depends on the value of the vector eld not only
at that point, but in a neighbourhood. It is easy to see that from the algebraic point of
view this is due to the fact that the map X 7→ L(X) is itself a dierential operator and
60
Section 5: Tensor Fields; Lie Derivative
not an A-linear map. For instance, if f ∈ A(M), and α is a 1-form, we have
(L(fX)α)(Y ) = (fX)α(Y ) −α([fX, Y ])
= f (Xα(Y )) − α(f[X, Y ] −(Y f )X)
= f X(α(Y )) − fα([X, Y ]) + (Y f )α(X)
= f (L(X)α)(Y ) + (Y f)α(X).
Thus we have
L(fX)α = fL(X)α + α(X)df.
In order to get a good notion of dierentiation on tensor elds, we need some ad-
ditional structure on the manifold. We will deal with this in some detail in Chapter
5.
61